Question

A body accelerates from rest for 5 seconds with a uninform acceleration of 9.8 m/s. What would be the final velocity of the body?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Final\:velocity=49\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Fiven :}} \\ \tt: \implies Time(t) = 5 \: sec \\ \\ \tt: \implies Acceleration(a) = 9.8 \: m/{s}^{2} \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Final \: velocity(v) = ?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies v = 0 + 9.8 \times 5 \\ \\ \tt: \implies v = 0 + 49 \\ \\ \green{\tt: \implies v = 49 \: m/s} \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \orange{ \tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{ \tt \circ \: s= ut+ \frac{1}{2} a {t}^{2} }$

Answer 2

Given

Body accelerates from rest.

Time taken = 5 seconds.

Uniform acceleration = 9.8 m/s²

To find

Final velocity of body

Solution

Here, as the body starts from rest,

⇒ Initial velocity (u) = 0 m/s

⇒ Time (t) = 5 seconds.

⇒ Acceleration (a) = 9.8 m/s²

We know equation of motion :

⇒ v = u + at

Putting values we get :

⇒ v = 0 + (9.8 × 5)

⇒ v = 0 + 49

⇒ v = 49 m/s

Therefore,

Final velocity of body is 49 m/s

_________________________

More equations of motion :

➝ v² = u² + 2as

➝ s = ut + ½at²

➝ a = (v - u)/t