Question

A body accelerates uniformly from 10 m/s to 25 m/s in 5 s. Find
(i) The velocity of the body after next five second.
(ii) The distance covered by the body in that time.

Answer 1

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→ Answer : V = 25 m/s , S = 87.5 m

→ Explanation :

Acceleration means 'Rate of change of velocity' or ' Change in velocity per unit time '

$u=10m/s,v=25m/s,t=5s\\\\=>a=\frac{v-u}{t} =\frac{25-10}{5}\\\\ =>a=3m/s^2$

(i) The velocity of the body after next five second.

Here

       $u=10m/s,v=?,a=3m/s^2,t=5s\\\\v=u+at\\\\v=10+3(5)\\\\=>v=25m/s$

(ii) The distance covered by the body in that time.

$u=10m/s,s=?,t=5s,a=3m/s^2\\\\s=ut+\frac{1}{2}.at^2\\\\ =>s=10(5)+\frac{1}{2}.3.(5)^2\\\\=>s=50+37.5\\\\=>s=87.5m$

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