A body accelerates uniformly from 10 m/s to 25
m/s in 5 s. Find [3]
(i) The velocity of the body after next five second.
(ii) The distance covered by the body in that time.
Answers
Answered by
0
Answer:
625
Explanation:
The initial velocity is
u= 0 m
s
−
1
The acceleration is
a
=
10
m
s
−
2
The time is
t
=
5
s
Apply the equation of motion
v
=
u
+
a
t
The velocity is
v
=
0
+
10
⋅
5
=
50
m
s
−
1
The distance travelled in the first
5
s
is
s
=
u
t
+
1
2
a
t
2
=
0
⋅
5
+
1
2
⋅
10
⋅
5
2
=
125
m
The distance travelled in the following
10
s
is
s
1
=
v
t
1
=
50
⋅
10
=
500
m
The total distance travelled is
d
=
s
+
s
1
=
125
+
500
=
625
m
Answered by
5
The initial velocity is
u = 0 m
s
-
1
The acceleration is
a
=
10
m
s
-
2
The time is
t
=
5
s
Apply the equation of motion
v
=
u
+
a
t
The velocity is
v
= 0
+
10
.
5
=
50
m
s
-
1
The distance travelled in the first
5
s
is
s
=
u
t
+
1
2
a
t
2
=
0
.
5
+
1
2
.
10
.
5
2
=
125
m
The distance travelled in the following
10
s
is
s
1
=
v
t
1
=
50
.
10
=
500
m
The total distance travelled is
d
=
s
+
s
1
=
125
+
500
=
625
m
Similar questions