Question

A body accelerates uniformly from 10m/s to 25m/s in 5 seconds. Find:
(i) The velocity of the body after the next five seconds.
(ii) The distance covered by the body in that time.
please give the answer in two different parts ​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Velocity\:after\:next\:5\:sec=40\:m/s}}}$

$\green{\tt{\therefore{Distance\:travel=250\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Initial \: velocity = 10 \: m/s \\ \\ \tt: \implies Velocity \: after \: 5 \: sec= 25 \: m/s \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Velocity \: after \: next \: 5 \: sec = ?\\ \\ \tt: \implies Distance \: travel \: in \: that \: time =?$

• According to given question :

$\tt \circ \: u = 10 \: m/s \\ \\ \tt \circ \: v = 25 \: m/s \\ \\ \tt \circ \: t = 5 \: sec \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 25 = 10 + a \times 5 \\ \\ \tt: \implies a = \frac{25 - 10}{5} \\ \\ \tt: \implies a = \frac{15}{5} \\ \\ \green{\tt: \implies a = 3 \: {m/s}^{2}} \\ \\ \tt \circ \: u = 10 \: m/s \\ \\ \tt \circ \: t = 10 \: sec \\ \\ \tt \circ \: a = 3 \: {m/s}^{2} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies v = 10 + 3 \times 10 \\ \\ \tt: \implies v = 10 + 30 \\ \\ \green{\tt: \implies v = 40 \: m/s} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies {v}^{2} = {u}^{2} + 2as \\ \\ \tt: \implies {40}^{2} = {10}^{2} + 2 \times 3 \times s \\ \\ \tt: \implies 1600 - 100 = 6 \times s \\ \\ \tt: \implies \frac{1500}{6} = s \\ \\ \green{\tt: \implies s = 250 \: m}$

Answer 2

GIVEN :-

A body accelerates uniformly from 10 m/s to 25 m/s in 5 seconds.

TO FIND :-

• The velocity of the body after the next five seconds.

• The distance covered by the body in that time.

SOLUTION :-

Initial velocity(u) = 10 m/s

Final velocity(v) = 25 m/s

Time(t) = 5 s

We know,

v = u + at

Substituting the values :-

⇒25 = 10 + a(5)

⇒25 - 10 = 5a

⇒15 = 5a

⇒a = 15/5

⇒a = 3 m/s²

(i) A/q,

Time = 5 + 5 = 10 s

Now, applying the formula :- v = u + at

v = 10 + (3 × 10)

⇒v = 10 + 30

⇒v = 40 m/s                       ---Answer

(ii)We know,

v² - u² = 2as

⇒(40)² - (10)² = 2 × 3 × s

⇒1600 - 100 = 6s

⇒1500 = 6s

⇒s = 1500/6

⇒s = 250 m                       ---Answer