Question

A body accelerates uniformly from 10m/s to 25m/s​ in 5s find velocity of the body in the next 5s

Answer 1

Answer:

Initial velocity of the body = 10m/s

final velocity of the body = 15m/

Time taken = 5s

uniform accelaration = (15-10)/5 = 1m/s²

velocity after next 5s = 20m/s

Because the body is in uniform motion

Distance travelled = (v+u)/2×t

v = 20m/s

u = 15m/s

time = 5s

distance = s = (20+15)/2×5 = 175/2 = 87.5m ans

I hope it will help you

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Velocity\:after\:next\:5\:sec=40\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial\:velocity(u) = 10 { \: m/s}\\\\ \tt: \implies Final\:velocity(v) = 25 { \: m/s} \\ \\ \tt: \implies Time(t) = 5\: sec \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Velocity\:of\:body\:in\:next\:5\:sec=?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 25 = 10+ a \times 5 \\ \\ \tt: \implies 25-10=a\times 5\\\\ \tt:\implies a=\frac{15}{3}\\ \\ \green{\tt: \implies a = 3 \: m/s^{2}}$

$\tt \circ \: Acceleration = 3 { \: m/s}^{2} \\ \\ \tt \circ \: Time = 5 \: sec \\ \\ \tt \circ \: Initial \: velocity = 25 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies v = 25 + 3 \times 5 \\ \\ \tt: \implies v = 25 + 15 \\ \\ \green{\tt: \implies v = 40 \: m/s}$