A body accelerates uniformly from rest at the rate of 3m/s for 8 sec calculate the distance covered by the body during the acceleration
Answers
Given data : A body accelerates uniformly from rest at the rate of 3 m/s² for 8 sec.
To find : Calculate the distance covered by the body during the acceleration.
Solution : A/C to given data;
- Initial velocity = 0 (A body accelerates uniformly from rest )
- acceleration = 3 m/s²
- Time taken = 8 sec
Now, we use kinematical equation;
➜ s = ut + ½ at²
Where,
- u = initial velocity of the body
- a = acceleration of the body
- t = time taken by the body
- s = displacement
➜ s = ut + ½ at²
➜ s = 0 * 8 + ½ * 3 * (8)²
➜ s = ½ * 3 * 64
➜ s = 3 * 32
➜ s = 96 m
Answer : Hence, the distance coverd by the body during the acceleration is 96 m.
More info :
Kinematical equations
- v = u + at
- s = {(u+v)/2} * t
- s = ut + ½ at²
- s = vt - ½ at²
- v² = u² + 2as
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