Question

A body acclerates from rest to a velocity of
144 kmine. Find the distance Covered by the
body in 20 second​

Answer 1

Answer:

2880 kmine

Step-by-step explanation:

144×20=2880 kmine

Answer 2

Answer:

Initial speed u = 0; final speed v = 144 km/hr = 144 x (5/18) = 40 m/s ;

acceleration a is obtained from the formula, "v=u+at",

i.e. a = v/t = 40/20 = 2 m/s²

distance covered in 20 s:- S = ut+ (1/2) a t² = (1/2)×2×20x20 = 400 m

Hyung/Noona if this is correct plz mark me as brainliest