A body aced upon by 3 given forces is under equilibrium if f1=10n f2=6n find the value of f3 and angle r=0
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∑F
x
=0⇒6sinθ−10sin37
sinθ=
6
10
sin37
θ=90
∑F
y
=0⇒6cosθ+10cos37=F
3
6cos90+10cos37
F
3
=8N
solution
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