Question

A body acquires a speed of 15m/s after covering a distance of 50 m moving with
uniform acceleration of 2m/s?. Find its initial velocity.​

Answer 1

Explanation:

Given Final velocity, v=15m/s

Acceleration, a=2m/s² and distance, s=50m

Apply the formula v²-u²=2as

To find initial velocity (u),

15²-u²=2×2×50

i.e. 225-u²=200

Therefore u²=25

u = +5 and -5. (since 5² and (-5)² gives 25)

But velocity can never become negative, so neglect -5

Therefore initial velocity = 5m/s.

Hope u understood!

Answer 2

Answer

• Initial velocity , u = 5 m/s

Given

• A body acquires a speed of 15 m/s after covering a distance of 50 m moving with  uniform acceleration of 2 m/s

To Find

• Initial velocity

Solution

Final velocity , v = 15 m/s

Distance , s = 50 m

Acceleration , a = 2 m/s²

Initial velocity , u = ? m/s

Apply 3 rd equation of motion ,

⇒ v² - u² = 2as

⇒ 15² - u² = 2 ( 2 ) ( 50 )

⇒ 225 - u² = 200

⇒ u² = 25

⇒ u = 5 m/s

So , Initial velocity , u = 5 m/s