Question

. A body, acted upon by a force of 50 Newton is displaced through a distance of 10 metre in a direction making an angle of 60° with the force. Calculate the work done by the force

Answer 1

Answer: The work done by the force i 250 J.

Explanation:

Given that,

Force F = 50 N

Distance d = 10 meter

Angle $\theta = 60^{0}$

We know that,

The work done is the product of the force and distance.

The work done is

$W = fdcos\theta$

$W = 50\times10\times cos60^{0}$

$W = 250 J$

Hence, the work done by the force is 250 J.

Answer 2

"Given:

Force = 50 N

Distance, S = 10 m

Angle, $\theta=60^{\circ}$

Solution:

Formula for work done is,

Work done, $W=FS \cos \theta$

$W=(50)(10) \cos 60^{\circ}$

$W=500\left(\frac{1}{2}\right)$

$W=\frac{500}{2}$

Work done = 250 Nm

A work is done when an object is displaced over a distance. The Unit of work done is Nm. It has both direction and magnitude, so it is a vector quantity. When the "work done" is not in a "straight line" then the angle is added to the formula."