Question

A body acted upon by a pressure of 14700 pa which is kept at a certain height. take g=10 m/s and density 1.47kg m^3 find the height

Answer 1

Answer:-

$\red{\bigstar}$ Height $\large\leadsto\boxed{\rm\purple{1000 \: m}}$

• Given:-

Pressure = 14700 Pa

Density = 1.47 kg/m³

g = 10 m/s²

• To Find:-

Height = ?

• Solution:-

We know,

$\pink{\bigstar}$ $\large\boxed{\sf\purple{P \: = h \: \rho \: g}}$

here,

P = pressure

h = height

ρ = density

g = acceleration due to gravity

• Substituting in the Formula:-

$\red{\bigstar}$ P=hρg

→ $\sf{14700 = h \times 1.47 \times 10}$

→ $\sf{14700 = h \times 14.7}$

→ $\sf{h = \dfrac{14700}{14.7}}$

→ $\bf\green{h = 1000 \: m}$

Therefore, the height at which the body is kept is 1000 m.