A body ascends a slope with a speed of 10m/s. If 105 J of energy of the body is lost due to friction , the height to which the body will rise is (take g =10ms^-2)?
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According to the work-energy principle,
P.E = K.E
mgh = 1/2 mv² - 105 ( as 105 J of body energy is lost due to friction)
2gh = v² - 105m
2(10)h = 10² - 105m
20h = 100 - 105m
h = (100 - 105m) / 20
h = (20 - 21m) / 4
This is the required expression for calculating the height, where m is mass in kg.
P.E = K.E
mgh = 1/2 mv² - 105 ( as 105 J of body energy is lost due to friction)
2gh = v² - 105m
2(10)h = 10² - 105m
20h = 100 - 105m
h = (100 - 105m) / 20
h = (20 - 21m) / 4
This is the required expression for calculating the height, where m is mass in kg.
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