Question

a body at rest explodes into two pieces of unequal mass the parts will move

Answer 1

☸the heavier mass will move with less velocity than the lighter one...

☸this is because of CONSERVATION OF MOMENTUM

☸so.. here... the momentum of body before explosions is 0 kg m/s .... because initially the body is at rest and --- > >momentum=mv=m(0)=0kgm/s

▶so after explosion the total momentum must be the same as the initial momentum
_______________________________
let M>m {masses of the parts of body after explosion}
=> M=mass of heavier part
=> v2 = velocity of heavier part
=>m=mass of lighter part
=> v1=velocity of lighter part
______________________________

=> 0=mv1+Mv2

=> mv1=Mv2{magnitude}

➡ as M>m
➡ V1>v2

hence the lighter part will move with greater velocity....

hope it helps you...☺☺

Answer 2

Answer:

in opposite directions with unequal speeds