Physics, asked by Samiksha3531, 11 days ago

A body at rest has a mass of 3 kg. A force of 12 N acts on it for 2 s. Calculate its
(a) velocity attained and
(b) change in momentum.


Ans:
(a) 8ms
(b) 24 kg ms ​

Answers

Answered by mohantypreet2
3

Answer:

Explanation:

mass of body, m = 4 kg

force on body, f = 12 N

time, t = 2s

.. f = ma

a = f/m

a = 12/3 = 4 m/s²

.. velocity = acceleration x time

v = at

v = 4 x 2= 8 m/s

.. momentum = mass x velocity

p = mv

p=3×8=24 kg .m/s

Answered by romanyadav86
0

Answer:

p= 48Kg .m/s

v = 16 m/s ..

Explanation:

mass of body, m = 3kg

force on body, f = 12N

time, t = 4 s

.. f = ma

a = f / m

a = 12/3 = 4m / (s ^ 2)

.. velocity = acceleration × time

V = at

v = 4 * 4 = 16m / s

.. momentum = mass × velocity

p = mv

p = 3 * 16 =48 Kg.m/s

by STM..

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