a body attains a velocity of 25ms-1 in 2 s with an acceleration of 4ms-2. the displacement of the body is
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we are given that -
v=25ms-1
time=2sec
a=4ms-1
u=?
By 1st equation of motion
v= u + at
25 = u+ 4*2
25-8=u
u=17ms-1
Displacement = v-u
s=25-17
s=8m
v=25ms-1
time=2sec
a=4ms-1
u=?
By 1st equation of motion
v= u + at
25 = u+ 4*2
25-8=u
u=17ms-1
Displacement = v-u
s=25-17
s=8m
Akshita2004:
change in position final - initial
it is asked to find the displacement i.e how far the object has moved after that velocity...
so you can find distance by 2nd eq. of motion
hmm....s=ut + 1/2 at^2......???
or s = (v^2 - u^2)/2a = 327/ 8 = 40.875m
you can edit ypur answer....
by third eq. of motion ans. = 42m
anyhow it is approx valu...
42 m answer is correct
ok now edit your answer and put 42m...in it
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