Question

A body attains a velocity of 25ms-1 in 2s
With an acceleration of 4ms-2 .the displacement of the body is

Answer 1

Answer:

78.125 m

Explanation:

$v^2-u^2=2as\\25^2-0^2=2(4)(s)\\625=8s\\s=78.125 m$

Answer 2

Answer: 58 m/s.

Explanation: By using, third law of motion,

s = u×t + 1/2 × a ×t^s

We get,

S= 25×2 + 0.5×4×2^2

= 50 + 8

= 58m/s.

Hope ur answer is cleared.