Question

A body builder exerts a force of 150 N against a bullworker and compresses it by 20 cm. Calculate the spring constant of the spring in the bullworker.

Answer 1

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

From the Question,

• Spring Force,F = 150 N

• Compression,x = 20 cm

To find

Spring Constant (k)

Spring Force is given by :

$\huge{ \boxed{ \boxed{ \orange{\rm{f = - kx}}}}}$

Since,

The object is getting compressed

$\rightarrow \: \sf{x = - 20 \: cm}$

But the measurement should be in meters

$\rightarrow \: \boxed{\sf{x = - 20 \times {10}^{ - 2}m }}$

Substituting the values,we obtain :

$\sf{150 = - k( - 20 \times {10}^{ - 2} )} \\ \\ \implies \: \sf{150 = 20k \times {10}^{ - 2} } \\ \\ \implies \: \sf{k = \frac{150 \times {10}^{ - 2} }{20} } \\ \\ \huge{\implies \: \sf{k = 7.5 \times {10}^{ - 2} Nm {}^{ - 1} }}$

Thus,the spring constant is 0.075 N/m

Answer 2

The spring constant of the spring in the bull worker is 750 N/m .

Explanation:

Step 1:

The builder of the body exerts strength and compression

Force F = 150 N  

x = 20 cm = 0.2 m  

Step 2:

We know that  

F = kx

Where F is the applied force ,  

k is the spring constant and  

x is the deflection of spring.  

Step 3:

Now from the formula ,

we get

$\begin{aligned}k &=\frac{F}{x} \\k &=\frac{150}{0.2} \\k=& 750 \mathrm{N} / \mathrm{M}\end{aligned}$

Thus, the spring constant of the spring in the bull worker is 750 N/m .