Question

A body centered cubic element of density 10.3gm per cm3 has a cell edge of 314 pm calculate the atomic mass of the element

Answer 1

Answer:

Density of element, ρ = 10.3 g cm

−3

Cell edge a=314 pm

N

A

=6.023×10

23

mol

−1

Atomic mass = 96 g mol

−1

P=

a

3

×N

A

Z×M

Z=

M

P×N

A

×a

3

=

96gmol

−1

10gcm

−3

×10

−30

cm

3

×6.023×10

23

mol

−1

= 2

The structure of the crystal lattic is B.C.C