Question

A body changes its velocity from 2m/s to 5 m/s in 2 mint .Find a) distance travelled by the body in 1 mint and 2 mints.

Answer 1

a= 1.5 m/ sec^2
for first one minute
V =u + at
v= 2+ 1.5×1
v= 3.5 m/sec
now applying third equation of motion we get
v^2=u^2+2as
by solving this equation you get the value of s
for 2nd minute initial velocity(u) = 3.5 ,v=5m/sec ,a= 1.5 m/sec^2
again apply the third equation of motion you will get to your answer

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