Question

a body cimplete 100 3/4 revolution on in a circular path of its radius r then its displacement will be
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Answer 1

Displacement of the object is $\sqrt{2}r$

EXPLAINATION

⇒ After completing 100 revolution, the body is in its original position.

⇒ After the remaining 3/4 revolution is completed, the body is 90º away from its original position.

So, displacement

= shortest distance between initial and final point

$=\sqrt{r² + r²}$

$=\sqrt{2r²}$

$=\sqrt{2}r$