a body consists of right circular solid cone of height 40 mm and radius 30mm placed on solid hemisphere of radius 30mm of the same material .find the position of cg Of the body
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Given a body consists of right circular solid cone of height 40 mm and radius 30 mm placed on solid hemisphere of radius 30 mm of the same material .find the position of centre of gravity Of the body
- Volume of hemisphere is
- x1 = 2/3 π r^3
- = 2/3 x 3.14 x (30)^3
- = 18000 x 3.14
- = 56,520 mm^3
- Also we have
- y1 = 3r/8
- = 3 x 30 / 8
- = 11.25 mm
- Now we have volume of right circular cone as
- x2 = 1/3 π r^2 h
- = 1/3 x 3.14 x 30 x 30 x 40
- = 37,680 mm^3
- Also we have y2 = r + h/4
- = 30 + 40/4
- = 40 mm
- Distance between centre of gravity of body and bottom of hemisphere will be
- z = x1y1 + x2y2 / x1 + x2
- = 56,520 x 11.25 + 37,680 x 40 / 56,520 + 37.680
- = 635850 + 1507200 / 94200
- = 2143050 / 94200
- = 22.68 mm
Reference link will be
https://brainly.in/question/7910061
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