A body constrained to move in the y direction is subjected to a force F= 2i + 15j + 6k N. The work done by this force in moving the body through a distance of 10m along v-axis is?
Answers
Answered by
333
vector F = 2 i + 15 j + 6 k Newtons, where i , j , k are unit vectors along axes.
s = displacement = 10 j meters
work done = F . s = (2 i + 15 j + 6 k) . 10 j Joules
= 20 i . j + 150 j . j + 60 k . j
= 150 Newtons
as i . j = 0 and k . j = 0 and j . j = 1
s = displacement = 10 j meters
work done = F . s = (2 i + 15 j + 6 k) . 10 j Joules
= 20 i . j + 150 j . j + 60 k . j
= 150 Newtons
as i . j = 0 and k . j = 0 and j . j = 1
Answered by
18
Explanation: ( WORKDONE = FORCE.DISPLACEMENT)
(-2î + 15j + 6k)N . 10j
And the Answer is 150J because all the value of distance is 0î and 0k which when we multiple with -2î and 6k is 0 (ZERO)
THEREFORE,ONLY WE HAVE MAGNITUDE OF Y AXIS THAT'S WHEN WE MULTIPLE THE ANSWER COME 15.10 = 150J
Similar questions