A body constrained to move in the y direction is subjected to a force F= 2i + 15j + 6k N. The work done by this force in moving the body through a distance of 10m along v-axis is?
Answers
Answered by
24
F= 2i +15j + 6k N
displacement, s= 10j m
work done, W = F.s
=(2i +15j + 6k ).10j
= 0 + 150 +0
= 150 N-m or Joule
displacement, s= 10j m
work done, W = F.s
=(2i +15j + 6k ).10j
= 0 + 150 +0
= 150 N-m or Joule
Answered by
11
Force =2i+15j+6k
Displacement =10
Work =force ×displacement
=2×i×10j+15×j×10j+6×k×10j (we know i×j=0,j×j=1,k×j=0)
=2×0×10+15×1×10+6×0×10
=0+150+0
=150j answer
I hope my answer is right
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