Question

A body cools from 70 degree Celsius to 50 degree celsius in 5 minutes. temperature of surroundings is 20 degree celsius. temperature after next 10 minutes is

Answer 1

The temperature after next 10 minutes is Tf = 26° C.

Explanation:

dθ / dt  = K( θ1 + θ2 / 2 − θo)

+ 20 /5 = - K ( 70 - 20)

K = + 20 / 5 x 50

K = 2 / 25

T - 50 / 10 = - 2/25 (50 - 20)

T - 50 / 10 = - 2/25 x 30

T - 50 = - 24

T = 26

Tf = 26° C

Thus the temperature after next 10 minutes is Tf = 26° C.

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What would be the final temperature of mixture of 50 g of water at 20 C temperature and 50 g of water at 40 C temperature?

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