Question

A body cover a distance of 45m in the 7th second and 75m during its 12th second of motion . determine the initial velocity and the acceleration of the particle​

Answer 1

Answer:

42, 6

v7th = 45

v12th = 75

a = ( 75-45)/ 5= 6 m sec^-2

45 = u+ 1/2*6*1

45= u+ 3

u= 42 meter/sec