Physics, asked by abhishekkumarlk, 1 year ago

A body cover one-third of the distance with a speed v1 the second one-third of the distance with a speed v2 and the remaining distance with a speed v3. The average speed is

Answers

Answered by nayan12383
0
The average speed will be (v1+v2+v3)÷ 3.
Answered by pranjalbhujel86
2

Average velocity = displacement / total time

Let the displacement = s

\frac{s}{ \frac{s}{3.10}+ \frac{s}{3.20} + \frac{s}{3.30} }

\frac{s}{ \frac{s}{30} +\frac{s}{60} +\frac{s}{90} }

\frac{s}{s( \frac{1}{30} +\frac{1}{60} +\frac{1}{90} )}

\frac{1}{ \frac{6+3+2}{180} }

\frac{1}{ \frac{11}{180} }

180/11 = 16.36 m/s

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