A body cover one-third of the distance with a speed v1 the second one-third of the distance with a speed v2 and the remaining distance with a speed v3. The average speed is
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The average speed will be (v1+v2+v3)÷ 3.
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Average velocity = displacement / total time
Let the displacement = s
\frac{s}{ \frac{s}{3.10}+ \frac{s}{3.20} + \frac{s}{3.30} }
\frac{s}{ \frac{s}{30} +\frac{s}{60} +\frac{s}{90} }
\frac{s}{s( \frac{1}{30} +\frac{1}{60} +\frac{1}{90} )}
\frac{1}{ \frac{6+3+2}{180} }
\frac{1}{ \frac{11}{180} }
180/11 = 16.36 m/s
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