A body cover the distance of L metre along a semicircular path. Calculate the magnitude of displacement of the body and ratio of distance to displacement.
aayushpathak94:
hello dear swetha... sorry for my mistake... pardon me...
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hello swetha dear friend again here's your answer....
in a semicircular path when a body travels.... it covers L metres.....
now we know that the distance I. e of semicircle is π×r ((taking it as 1)))
now the displacement would be 2×r (((taking it as 2))
now the ratio of distance to displacement would be
.....
(π×r) / 2×r == π\r
now if the value of r is known to you, you can calculate the answer.... by taking π= (22/7) /r...
Hope it helps you...
in a semicircular path when a body travels.... it covers L metres.....
now we know that the distance I. e of semicircle is π×r ((taking it as 1)))
now the displacement would be 2×r (((taking it as 2))
now the ratio of distance to displacement would be
.....
(π×r) / 2×r == π\r
now if the value of r is known to you, you can calculate the answer.... by taking π= (22/7) /r...
Hope it helps you...
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