Question

A body covered a distance of 5m along a semi circular path. the ratio of distance to its displacement ​

Answer 1

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$\tt\pi \: r \: \: = \: \: 5$

$\tt \dfrac{22}{7} \times r \: \: = \: \: 5$

$\tt\:r \: \: = \: \: \: \dfrac{5 \times 7}{22}$

Displacement = 2r

$\tt\dfrac{distance}{displacement} \: = \: \dfrac{\pi \: r}{2r} = \: \dfrac{11}{7}$

Answer 2

Step-by-step explanation:

Distance=5m

Distance is Along a semi circular path.

So the measurement of distance=1/2*2πr

=πr

Given that πr=5m

So r=5/π m

Displacement is the shortest distance

So displacement=2r

=2*5/π. (from above)

Ratio of distance to it's displacement=5:2*5/π =5:10/π = 5:3.18=5:3.9(approx.)=5:4(approx.)

Hence Ur answer is 5:4(approx.)