A body covered a distance of 5m along a semicircular path.The ratio of distance to displacement is?
A.11:7
B 12:5
C 8:3
D 7:5
E None
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Given,
Distance covered by a body along a semicircular path = 5m
To Find,
The ratio of distance to displacement.
Solution,
Since we are given the distance traveled by the body = 5m so we need to calculate the displacement of the body
Displacement of the body = 2r, where r is the radius of the semicircle.
Now,
πr = 5
r = 5/π = 5*7/22 = 35/22
Now,
2r = 2(35/22) = 35/11
So, the ratio of distance to displacement will be,
Distance:Displacement = 5:35/11
= 11:7
Hence, the ratio of distance to displacement is 11:7.
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