Question

A body covered a distance of 5m along semicircular path. How the ratio of distance to displacement is 11:7?

Answer 1

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Answer 2

Given:

Distance covered on semicircular path = 5m

To find:

The ratio of distance to displacement

Solution:

Let R be the radius of the semi-circular path

When the body covers a distance of π.R (from one endpoint of diameter to its another end), the displacement = length of diameter = 2 R

Given that distance is 5

So we can assume that π.R = 5

or R = 5/ π

Now, displacement = 2 R = 2 X 5/ π = 10 / π

The ratio of distance covered to displacement will be Distance / Displacement

= $\frac{5}{10/\pi}$

=  π / 2

= 11/ 7  (Taking  π = 22/7)

Hence, the ratio of distance to displacement is 11:7.