Question

a
body covered a distance of L meter along a semicircular path calculate
the magnitude of displacement of the body
and ratio of distance to displacement​

Answer 1

Let r be the radius of the semicircular path

Since L is the distance along the semi-circular path,

=> L = πr

=> r = L/π

Therefore,displacement of the body = 2(r)

                                                         = 2L/π

So,the ratio of distance to displacement = L : 2L/π

On canceling both the L,we get:-

Ratio of distance to displacement = π : 2

If getting confused at any point Please see the attachment below.

Please mark my answer as the brainliest answer....

Answer 2

Answer:

Hope helpful please follow me