Question

A body covered a distance of z metre along a sicircular path.Calculate the magnitude of displacement of the body, and the ratio of distance to displacement​

Answer 1

Answer:

A body covered a distance of z metre along a semicircular path.

If it is a circular path then the distance covered by the body will be 2πr. But here, body covered a semi-circular path.

(Means, half of the circular path i.e. 2πr/2 = πr)

So, distance covered by body = πr

Let us assume that the radius of the semicircular path is (r).

Radius = Diameter/2

2 × Radius = Diameter

2r = Diameter

What we have to find? We have to find the magnitude of displacement of the body, and the ratio of distance to displacement.

Now, Displacement = 2r i.e. Diameter of semicircular path

Given in question that, the body covers a distance of (z) meter.

Distance = z

Now,

Distance is z and diameter is 2r which is equal to z.

i.e. 2r = z

r = z/2

So, Distance = πr = πz/2

And from above we have displacement = 2r

And 2r = z. So, Displacement = z

Now,

Distance/Displacement = (πz/2)/z = πz/2z = π/2 [ Answer. ]

Explanation: