A body covered a distance of z metre along with semicircular path calculate the magnitude of displacement of the body and the ratio of distance to displacement
Answers
Answer:-,
The magnitude of displacement is 2 [A/ π] and ratio of distance to displacement is π : 2
Explaination:-
Consider r as the radius of semicircular path.
When a body covers distance of x meter along a circular path, distance covered by body will be 2π r.
But here body is covering distance along semicircular path. So distance covered by body will be π r.
Now Let’s find the displacement of the body.
Distance covered by body, A = π r ------(1)
Displacement = Diameter of the semicircular path = 2r ----- (2)
Putting the value of r from equation (1) to equation (2),
Displacement = 2 [A/ π]
Ratio of distance to displacement = A : 2A/ π = π : 2
ANSWER
displacement = z
displacement = zratio = π/2
FORMULA
PERIMETER OF SEMICIRCLE = πr
CONCEPTS
DISPLACEMENT = SHORTEST DISTANCE BETWEEN INITIAL AND FINAL POSITION
DISTANCE = TOTAL DISTANCE
MISUNDERSTANDING HERE
HERE WE HAVE GIVEN DIAMETER AS Z SO WE HAVE TO FIND ALL VALUES IN TERMS OF Z NOT IN TERMS OF RADIUS
SOLUTION
DISTANCE = Z
and diameter 2r (where r is radius) equal to z
as this is semicicular path of particle
2r = z
r = z/2
now
DISTANCE = πr = π z
2
DISPLACEMENT = 2r = z
DISTANCE
DISPLACEMENT
= > πz/2
z
=> π/2
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