Question

a body covers 1/4 distance in 10 km/h next 1/4 distance in 20 km/h next 1/4 in 30 km/h and last 1/4 in 40 km/h.find the average speed​

Answer 1

Explanation:

Answer

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Correct option is

C

48 kmh

−1

Total distance covered by car = 60 km

And, total time taken in journey t=t

1

+t

2

t=

v

1

s

1

+

v

2

s

2

  =

60

30

+

40

30

  =

4

5

 h

Therefore, Average Speed=

Total Time

Total Distance

=

4

5

 h

60km

=48 km/h

Answer 2

Answer:

$Total \: distance \: covered \: by \\ car \: = \: 60 km$

$And, \: total \: time \: taken \: in \\ journey \: t=t$

$t = t1 + t2$

$t = \frac{s1}{v1} + \frac{s2}{v2}$

$= \frac{30}{60} + \frac{30}{40}$

$= \frac{5}{4} h$

$\blue\therefore{ \green \: {Average \: Speed= </p><p> \: \frac{</p><p>Total \: Distance}{</p><p>Total \: Time}}}$

$\frac{60 \: km}{ \frac{5}{4}h } = 48 \: km \h$

=48 km/h