Question

A body covers 10m in 4th second and 15m in 6th second of its uniform accelerated motion. How far will it travel in next 3 second..???​

Answer 1

Answer:

S=u+1/2a(2n-1)

10=u+1/2a(7)...(1)

15=u+1/2a(11)...(2)

Subtract eq(1)&(2)

a=5/2m/s^2

U=5/4m/s

After next third second

S9=5/4+1/2×5/2(2×9-1)

S9=22.5m

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