A body covers 10m in 4th second and 15m in 6th second of its uniformly accelerated motion. How far will it travel in the next 3rd seconds.
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20m in 8th travel in the next 3rd
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S=u+1/2a(2n-1)
10=u+1/2a(7)...(1)
15=u+1/2a(11)...(2)
Subtract eq(1)&(2)
a=5/2m/s^2
U=5/4m/s
After next third second
S9=5/4+1/2×5/2(2×9-1)
S9=22.5m
I hope it will benefit you and best of luck
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