Question

A body covers 12 min 2nd second and 20m in 4th second. How much distance will it cover in 4 seconds after the 5th second? ​

Answer 1

Answer:

n

=u+a/2(2n−1)

s

2

=12

⇒12=u+a/2(2×2–1)

⇒12=u+3a/2 ………. (1)

s

4

=20

⇒20=u+a/2(2×4–1)

⇒20=u+7a/2 ………. (2)

Subtract equation (1) from (2)

s=4a/2

⇒a=4ms

−2

12=u+3/2×4

⇒u=6ms

−1

Distance covered in the 4 seconds after 5

th

second,

=S

9

–S

5

=u(9)+1/2a(9)

2

–[u(5)+1/2a(5)

2

]

=4u+a/2(81–25)

=4×6+4/2×56=136m.

Explanation:

this is the answer

Answer 2

Answer:

Explanation:

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