a body covers 20 km with 18 km per hour and next 40 km with 36 km per hour find its average velocity
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Let the total distance covered by bus be s km
As we know that speed=Distancetimespeed=Distancetime
Which gives, time=Distancespeedtime=Distancespeed
Time for first third is (t) = s320s320
Time for two third is (t′)=2s360(t′)=2s360
Now, we also know that
Averagespeed=TotaldistanceTotaltimeAveragespeed=TotaldistanceTotaltime
Averagespeed=st+t′Averagespeed=st+t′
Putting the values oft,t, &t′t′ from above we get
Averagespeed=ss320+2s360Averagespeed=ss320+2s360
Averagespeed=ss3×20+2s3×60Averagespeed=ss3×20+2s3×60
Averagespeed=ss3×20+2s3×60Averagespeed=ss3×20+2s3×60
Averagespeed=ss60+2s180Averagespeed=ss60+2s180
Averagespeed=s3s+2s180Averagespeed=s3s+2s180
Averagespeed=s5s180Averagespeed=s5s180
Averagespeed=s×1805sAveragespeed=s×1805s
Averagespeed=36Km/h
As we know that speed=Distancetimespeed=Distancetime
Which gives, time=Distancespeedtime=Distancespeed
Time for first third is (t) = s320s320
Time for two third is (t′)=2s360(t′)=2s360
Now, we also know that
Averagespeed=TotaldistanceTotaltimeAveragespeed=TotaldistanceTotaltime
Averagespeed=st+t′Averagespeed=st+t′
Putting the values oft,t, &t′t′ from above we get
Averagespeed=ss320+2s360Averagespeed=ss320+2s360
Averagespeed=ss3×20+2s3×60Averagespeed=ss3×20+2s3×60
Averagespeed=ss3×20+2s3×60Averagespeed=ss3×20+2s3×60
Averagespeed=ss60+2s180Averagespeed=ss60+2s180
Averagespeed=s3s+2s180Averagespeed=s3s+2s180
Averagespeed=s5s180Averagespeed=s5s180
Averagespeed=s×1805sAveragespeed=s×1805s
Averagespeed=36Km/h
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