Question

a body covers 200cm in the first 2 seconds and 220cm in the next two seconds what will be it' s velocity at the end of 7 seconds ? also find the displacement in 7 seconds​

Answer 1

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Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given by

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,420=6u+18a

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,420=6u+18aUpon solving, this gives u = 115 cm/s and a = -15 cm/s

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,420=6u+18aUpon solving, this gives u = 115 cm/s and a = -15 cm/sSo velocity at the end of 7 seconds is given by:

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,420=6u+18aUpon solving, this gives u = 115 cm/s and a = -15 cm/sSo velocity at the end of 7 seconds is given by:v=u+at

Assume that the body is under uniform acceleration here. Then, the total distance d traveled after the first t seconds is given byd=ut+1/2at2Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:200=2u+2a where u is in cm/s and a is in cm/s/s.Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,420=6u+18aUpon solving, this gives u = 115 cm/s and a = -15 cm/sSo velocity at the end of 7 seconds is given by:v=u+at= 115 - 105 = 10 cm/s

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