A body covers 20km with a speed of 40km/h and next 20 km with a speed of 30km/h .Calclate average speed
Anonymous:
Make this sum simple by using sexy theorem
sorry but i don't know apart from this method
Answers
Answered by
0
speed=40 kmh ;30kmh
distance= 20km ;20km
time=d/s= 40+30/20+20
=70/40=1.75kmh
distance= 20km ;20km
time=d/s= 40+30/20+20
=70/40=1.75kmh
what u did bro? after distance
No it is not like that
Answered by
0
The total distance which is given to us during the first part = 20 km
The speed by which it travels for the first path = 40 km/hr
Now you can calculate the time
Time = Distance/Speed
Therefore t1= 20/40 = 1/2 hr
The total distance which is given to us during the second part = 20 km
The speed which is given to us during the second part = 30 km/hr
Same here find the time:
t2= Distance/Speed
20/30= 2/3 km/hr
Now for calculating average speed : Total Distance/ Total time Taken
As we know the total distance is 20+20 = 40km
While the time is = t1+t2= 1/2 +2/3
solving the time part first: 1/2+2/3
7/6 hr (taking 6 as the LCM)
Now substitute the values = 40/7/6
40*6/7 (as 6 was below the denominator we multiplied it with the top)
= 240/7= 34.28 km/hr
The speed by which it travels for the first path = 40 km/hr
Now you can calculate the time
Time = Distance/Speed
Therefore t1= 20/40 = 1/2 hr
The total distance which is given to us during the second part = 20 km
The speed which is given to us during the second part = 30 km/hr
Same here find the time:
t2= Distance/Speed
20/30= 2/3 km/hr
Now for calculating average speed : Total Distance/ Total time Taken
As we know the total distance is 20+20 = 40km
While the time is = t1+t2= 1/2 +2/3
solving the time part first: 1/2+2/3
7/6 hr (taking 6 as the LCM)
Now substitute the values = 40/7/6
40*6/7 (as 6 was below the denominator we multiplied it with the top)
= 240/7= 34.28 km/hr
Similar questions