A body covers 20m in the 2nd second and 40m in 4th second of its motion . if its motion is uniformalyy acellarted how much accelarted how much distance will it cover in the 7th second of its motion ?
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Let us draw a diagram for clear understanding,
So, v = s/t
= 60/6
=10m/s
in next 7 second distance would be,
s=vt
=>s=70m
mark brainelist please
So, v = s/t
= 60/6
=10m/s
in next 7 second distance would be,
s=vt
=>s=70m
mark brainelist please
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