a body covers a distance from point A to point B with a speed of 48 km /hr and return back again return to the point B with a speed of 24 km/h find the average speed and average velocity of the body ?
Answers
Answered by
2
average speed = 48+24/2 = 72/2 = 36km/hr
average velocity = 0 (it is coming back so the displacement is 0 therefore average velocity is 0)
average velocity = 0 (it is coming back so the displacement is 0 therefore average velocity is 0)
uneq95:
your answer is wrong and you do not understand the concept well.
oh,i am sorry
my bad!
Answered by
0
Let the distance covered by the body be d km.
Time taken by the body to travel from A to B
t1 = distance/speed = 2d/48
Time taken by the body to travel from B to A
t2 = distance/speed = 2d/24
Average speed = total distance/ total time
= (2d + 2d)/(t1+t2)
= 4d/(2d/48+2d/24)
= 2d/(3d/48)
= 32 km/hr
Average velocity = net displacement / total time
Since, the body returns to its initial position, the net displacement is zero.
Hence, its average velocity is zero km/hr.
Time taken by the body to travel from A to B
t1 = distance/speed = 2d/48
Time taken by the body to travel from B to A
t2 = distance/speed = 2d/24
Average speed = total distance/ total time
= (2d + 2d)/(t1+t2)
= 4d/(2d/48+2d/24)
= 2d/(3d/48)
= 32 km/hr
Average velocity = net displacement / total time
Since, the body returns to its initial position, the net displacement is zero.
Hence, its average velocity is zero km/hr.
Similar questions