Question

A body covers a distance of 100m in 5 Seconds and 200m in 10 Seconds and another 100m is 4 seconds if the last 50m is covered in 1 second then find the average speed ​

Answer 1

Explanation:

Distance travelled in first 2 seconds=200cm

s=ut+21at2

200=2u+21a×4

u+a=100→(1)

Distance travelled in next 4 sec= 220 cm

Distance travelled in first 6 sec= 420 cm

420=u×6+21a×36

70=u+3a→(2)

Solving equation 1 and 2

2a=−30

a=−15cm/s2

From equation 1 ,u=115cm/s

v=u+at

v=115+(−15)(7)

v=10 cm/s

that is answer