Question

A body covers a distance of 10m/s with a velocity of 5m/s and further covers a distance of 20m with a velocity of 4m/s. Find the average velocity for the motion

Answer 1

Answer:

4.28 m/s

Explanation:

In first case, time elapsed = $distance\over velocity$ = 10/5 = 2 seconds.

In second case, time = $distance\over velocity$ = 20/4 = 5 seconds.

So, total time = 7 seconds.

Now, total distance covered = 10 + 20 = 30 metres.

Hence, average velocity = $Total~distance\over Total~time$

$v_{av}={30\over 7}\\\\v_{av}=4.28~m/s$

Answer 2

Answer:

Explanation:

Correct Question,

A body covers a distance of 10 m with a velocity of 5 m/s and further covers a distance of 20 m with a velocity of 4 m/s. Find the average velocity for the motion.

Answer,

Here, we have

Distance, D₁ = 10 m

Speed, S₁ = 5 m/s

Distance, D₂ = 20 m

Speed, S₂ = 4 m/s

To Find,

Average Speed.

We know that,

Time taken = Distance/Speed

⇒ Time taken in 1st case = 10/5 = 2 seconds

⇒ Time taken in 2nd case = 20/4 = 5 seconds

⇒ Total time taken = 2 + 5 = 7 seconds

Then,

⇒ Total distance covered = D₁ + D₂ = 10 + 20 = 30 m

we know that,

Average velocity = total distance/total time taken

⇒ Average velocity = 30/7

⇒ Average velocity = 4.28 m/s

Hence, the average velocity of body is 4.28 m/s.