Question

a body covers a distance of 5 metres along a semicircular Parth from its one end 2 you to another end . then the ratio of its distance covered to its displacement is ?​

Answer 1

Let r be the radius of the circle, then the semi-circumference πr = 5m

so r = 5/π

Then 5/πi is the position vector to the starting point and -5/πi is the position vector to the end point (i is the unit vector in the x-direction)

The distance is 5m, the displacement is -5/π – 5/π) = -10/πi = -3.183i

The ratio of distance to displacement is -5/3.183 = -1.57

Answer 2

now semicircular path is the semicircle

5 =pi×r

r =5/pi

then displacement is 2r = 10/pi

ratio is 5/(10/pi)

= 5×pi/10

= pi/2

= pi:2

or 11:7