a body covers distance d1 from a to b in time t with a velocity of v1. In time t, the body covers a distance d from b to c with velocity v2 and distance d from c to d with a velocity v3. Find the average velocity.
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Answer:
3v1v2v3 by v1+v2+v3
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Anonymous:
read the question
the answer is wrong
the distances covered from a to b and b to c are not equal
the distance covered from b to c is equal to the distances covered from c to d but not equal to the distance covered from a to b
u have taken all the 3 distances to be d/3 which means that they are equal whereas only 2 distances are equal the first one is not
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