Question

A body covers first 1/3 part of its journey with a velocity of 2m/s,next 1/3 part with a velocity of 3m/s and rest of the journey with a velocity of 6m/s.the average velocity of the body will be

Answer 1

Answer:average velocity = displace / time

so here we can assume total displacement covered is S

for 1st part time = displacement / velocity = (S/3) / 2

as displacement is S/3 and veocity is 2

similarly for 2nd part time = (S/3) / 3

3rd part time = (S/3) / 6

so total time = (S/6) + (S/9) + (S/18) = S (3+2+1) = S (6) = S

18 18 3

therefore average velocity = S = S3 = 3m/s

Explanation:

Answer 2

Answer:

Average velocity = total displacement/ total time taken  

Let the total displacement be s.

 

Thus, time taken for the first 1/3 part of journey is  

= (s/3)/2  =s/6  

Time taken for the second part of journey

=(s/3)/3 = s/ 9  

Time taken for third part of journey is

= (s/3)/6 = s/18  

 

Thus, total time taken to complete this journey is  

=(s/6)+(s/9)+(s/18)

= (s/3) x (6/6) = s/3  

Thus, t =s/3  

 

So, average velocity = s/(s/3) = 3 m/s  

 

Thus, average velocity of the body = 3m/s

Explanation: