Question

A body covers first half of the total distance with speed ‘u’, and
the second half with speed ‘v’. Calculate the average speed and
average velocity over the entire trip.

Answer 1

u+v/2

Explanation:

If a body covers first half ot the total distance with a speed u and same body covers the second half of the distance with speed named v then the average speed of total distance is equal to u+v/2 because here in 2 half's the distances velocity are different do it id. Mark as brainlist.

Answer 2

Answer:

Average velocity= Average speed= 2uv/u+v

Explanation:

Let the total distance covered by the body be 2s.

Time taken by the body to cover first half of the total distance⇒ t₁=s/u

Time taken by the body to cover second half of the total distance⇒ t₂=s/v

Average speed= total distance/total time= 2s/ t₁+ t₂

⇒2s/$\frac{s}{u}$+$\frac{s}{v}$=2uv/u+v

Average velocity= total displacement/ total time

As total displacement=total distance

∴ Average velocity= average speed= 2uv/u+v

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