a body covers half of its journey with a speed of 40 m/s what es the average sped during whole journey
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Avg speed=
total distance covered/ total time taken
Suppose the total distance=s
Time taken for first half t1=distance/speed=(s/2)/v1
=S/2v1
Time taken for second half=s/2v2
Total time=s/2v1)+(s/2v2)=s/2(1/v1+1/v2)
=S(v1+v2)/2v1v2
Avg speed= S/ total time taken
By solving this you get
Avg speed=2v1v2/(v1+v2)
So for this question=
2″40″60/100=48m/s
Short trick
Assume the distance as lcm of 40 and 60
240 total distance=240
Time taken in first half=120/40=3
Second half=120/60=2
Avg speed=total distance/total time taken
=240/5=48
Explanation:
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