Physics, asked by niket9540, 1 year ago

A body covers one third of the distance with speed v1 the second one third of the distance with speed v2 and the remaining distance with speed v3 average speed is....

Answers

Answered by pratheshs
0

Answer:

average speed = 3/(V1+V2+V3)

Explanation:

let us assume the distance as X

as given in the question,

the distance covered are X/3,X/3,X/3

the speed at these intervals are V1, V2, V3

let us assume the time as (X/3)/V1+(X/3)/V2+(X/3)/V3

average speed = total distance/ total time

=(X/3+X/3+X/3)/(X/3)/V1+(X/3)/V2+(X/3)/V3

=X/(XV1+XV2+XV3)/3

=3X/X( V1+V2+V3)

=3/(V1+V2+V3)

Similar questions